Advanced Organic Chemistry: The 1H NMR spectrum of phenol C6H5OH

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Interpreting and explaining the 1H proton NMR spectrum of phenol C6H5OH

[Author © Dr Phil Brown GRIC, PhD: Doc Brown's advanced level organic chemistry exam revision notes suitable for students of UK A level chemistry courses & US K12 grade 11, grade 12 and AP honors chemistry courses: Molecular spectroscopy - analysing the 1H NMR spectra of phenol [spectra page updated RE-EDIT]

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 H-1 proton NMR spectroscopy - spectra index

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Introductory note on the 1H NMR spectra of phenol

Students and teachers please note my explanation of the proton NMR spectrum of phenol is designed for advanced, but pre-university, chemistry courses.

The chemical shift δ splitting pattern effects for phenol are confined to a proton spin-spin coupling effects analysed using the n+1 rule for adjacent non-equivalent proton fields (n is the number of neighbouring protons in a non-equivalent different chemical environment for the phenol molecule).

It is assumed that the integrated intensities of the δ chemical shifts give the ratio of the protons in the different non-equivalent chemical environments of the phenol molecule.

The most common solvent used for investigating the 1H NMR spectrum of compounds like phenol, is CDCl3 and other deuterated solvents to avoid confusion with a 1H NMR signal, 2D (2H) has a different chemical shift.

1H proton nmr spectrum of phenol low/high resolution diagrams C6H6O C6H5OH analysis, interpretation of chemical shifts ppm, spin spin line splitting, n+1 rule, diagram H1 H-1 nmr for phenol explaining spin-spin coupling for line splitting doc brown's advanced organic chemistry revision notes

TMS is the acronym for tetramethylsilane, formula Si(CH3)4, whose protons are arbitrarily given a chemical shift of 0.0 ppm. This is the 'standard' in 1H NMR spectroscopy and all other proton resonances, called chemical shifts, are measured with respect to the TMS, and depend on the individual (electronic) chemical environment of the hydrogen atoms in an organic molecule - phenol here.

The chemical shifts quoted in ppm on the diagram of the H-1 NMR spectrum of phenol represent the peaks of the intensity of the chemical shifts of (which are often groups of split lines at high resolution) AND the relative integrated areas under the peaks gives you the ratio of protons in the different chemical environments of the phenol molecule.

PhenolC6H6OC6H5OH, (c) doc b(c) doc b

The molecular structure and naming of aromatic compounds

Interpreting the H-1 NMR spectrum of phenol

In terms of spin-spin coupling from the possible proton magnetic orientations, for phenol I have only considered the interactions of non-equivalent protons on adjacent carbon atoms e.g. R-CH-CH-X protons etc. but no splitting of or by the hydroxyl OH proton.

You need high resolution H-1 NMR spectrum of phenol to detect the different proton environments.

The 6 hydrogen atoms (protons) of phenol occupy 4 different chemical environments so that the high resolution NMR spectra should show 4 principal 1H peaks of different H-1 NMR chemical shifts (diagram above for phenol).

Chemical shifts (a) to (d) on the H-1 NMR spectrum diagram above for phenol.

Although there are 6 hydrogen atoms in the molecule, there are only 4 possible different chemical environments for the hydrogen atoms in phenol molecule.

The integrated signal proton ratio of 1:2:2:1 observed in the high resolution H-1 NMR spectrum, corresponds with the structural formula of phenol.

The high resolution 1H NMR spectrum of phenol

The high resolution spectra of phenol shows 4 groups of proton resonances and in the 1:2:2:1 ratio expected from the structural formula of phenol.

The ppm quoted on the diagram represent the peak of resonance intensity for a particular proton group in the molecule of phenol - since the peak' is at the apex of a band of H-1 NMR resonances due to spin - spin coupling field splitting effects - see high resolution notes on phenol below.

So, using the chemical shifts and applying the n+1 rule to phenol and make some predictions using some colour coding! (In problem solving you work the other way round!)

C6H5OH

Resonance (a) 1H Chemical shift for OH proton, 5.35 ppm.

This is observed as a singlet, there are no adjacent protons on the C1 carbon atom of the benzene ring, so no splitting observed via the n+1 rule.

See extra note on proton mobility and effect of adding D2O to the phenol sample.

 

aromatic benzene ring carbon atom positions in phenol 1H proton NMR spectroscopy

Reference diagram for the benzene ring protons of phenol

Ring positions in monosubstituted benzene compounds. Note that C2 = C6 and C3 = C5 for 1H nmr shifts i.e. they occupy the same chemical environment, this is an important point of symmetry for the 1H chemical shifts for these protons, so only three 1H shifts for the benzene ring protons.

One of the problems in interpreting NMR spectra is that the benzene ring CH proton 1H resonances (converted to chemical shifts) are often quite close together e.g. as in the 1H NMR spectrum of phenol.

Resonance (b) 1H Chemical shift for a CH protons on C2/C6, 6.84 ppm.

This 1H NMR resonance applies to the protons on the equivalent carbon atoms C2 and C6.

This resonance is split into a 1:1 doublet by the adjacent C3 or C5 CH proton (n+1 = 2).

Note there is no proton on carbon atom C1 that might increase the splitting effect.

Evidence for the presence of a CH group in the molecule of phenol

 

Resonance (c) 1H Chemical shift for a CH protons on C3/C5, 7.24 ppm.

This 1H NMR resonance applies to the protons on the equivalent carbon atoms C3 and C5.

This resonance is split into a 1:2:1 triplet by the adjacent CH protons on C4 and C6 on either side (n+2 = 3).

 

Resonance (d) 1H Chemical shift for a CH proton on C4, 6.93 ppm.

This 1H NMR resonance applies to the proton on carbon atom C4.

This resonance is split into a 1:2:1 triplet by the adjacent CH protons on C3 and C5 on either side (n+2 = 3).


EXTRA NOTE on why the OH proton chemical shift is usually observed as a singlet in phenols like phenol and how deuterium oxide can be used to identify the peak caused by the hydroxyl proton

EXAM BOARD NOTE: UK A‑level exam boards do not expect OH protons to show spin–spin splitting, nor do they expect students to predict or interpret any splitting caused by OH protons. In exam conditions, OH (alcohols, phenols) and NH (amines) signals are always treated as singlets, because rapid proton exchange removes observable coupling and what you see is a broad singlet.

Although extremely weak acids, there is constant exchanging of protons between alcohol molecules (R = alkyl groups of phenol or just the rest of the molecule).

R-O-H  +  H-O-R    R-O-H  +  H-O-R

The rate of proton transfer is increased by traces of water.

R-O-H  +  H-O-H    R-O-H  +  H-O-H

This cannot happen with the non-acidic C-H protons of alkyl groups in phenols like phenol.

This rapid proton transfer interferes with the field splitting effects of the hydroxyl O-H protons and carbon C-H protons and the spin-spin coupling effects disappears if enough deuterium oxide is present.

This phenomena can be used to identify the O-H proton resonance in phenols from other C-H proton resonances in hydroxyl molecules like phenol.

If deuterium oxide (D2O, where D = 2H) is added to the NMR alcohol sample, the 1H protons are rapidly replaced by 2H protons in the phenol molecule.

R-O-H  +  D-O-D    R-O-D  +  H-O-D

The 2H chemical shift frequency is different to the 1H chemical shift frequency, so the effect of D2O is to remove (or reduce intensity of) the chemical shift for the OH proton from the 1H NMR spectrum of phenol, thereby identifying the original 1H chemical shift as belonging to the hydroxyl group O-H proton and not a C-H benzene ring proton of the phenol molecule.


Key Features of Phenol's ΉH NMR Spectrum

Phenol (C6H5OH) has six protons: five aromatic hydrogens and one hydroxyl hydrogen.

  • Aromatic protons (δ ~6.8–7.4 ppm):
    • Multiplet due to coupling between adjacent protons on the benzene ring.
    • Integration: 5 H.
    • Characteristic of monosubstituted benzene derivatives.
  • Hydroxyl proton (δ ~4.5–7.0 ppm):
    • Broad singlet, variable chemical shift depending on hydrogen bonding and solvent.
    • Integration: 1 H.
    • Often exchangeable with D2O (disappears upon D2O shake).

Table of Chemical Shifts and Proton Assignments

δ (ppm) Range Proton Type Origin Integration
6.8–7.4, 6.84-6.93 ppm Aromatic H Five protons on benzene ring, but there are three 1H chemical shifts close together, 2 : 1 : 2 around the ring. 5
4.5–7.0, 5.35 ppm OH proton Hydroxyl group attached to ring 1

Sources: NMR data from NIST Chemistry WebBook


Common Misconceptions

  • Assuming OH always appears at δ ~1–2 ppm (like alcohols):
    In phenol, OH is deshielded by the aromatic ring and hydrogen bonding, so it shifts downfield (δ ~4.5–7.0 ppm).
  • Thinking OH proton always couples:
    The OH proton usually appears as a broad singlet due to rapid exchange, not as a coupled signal.
  • Miscounting aromatic protons:
    Students sometimes expect 6 aromatic protons; phenol has only 5 because one position is substituted by OH.
  • Overlooking D2O exchange test:
    The OH signal disappears after D2O addition, confirming its identity.

Exam Revision Tips

  • Integration check: Always confirm the proton ratio 5:1 (aromatic : OH).
  • Coupling pattern: Aromatic protons give a multiplet, not a simple singlet.
  • OH variability: Examiners expect recognition that OH chemical shift is solvent- and hydrogen bonding-dependent.
  • Comparison strategy: Contrast phenol with benzene (δ ~7.3 ppm, 6 H) and ethanol (OH δ ~2–5 ppm).
  • D2O shake test: Mentioning this in exam answers shows strong understanding of proton exchange.
  • Exam technique:
    1. Identify integration ratios.
    2. Assign aromatic versus OH signals.
    3. Comment on chemical shift variability.
    4. Relate to structure (monosubstituted benzene).

QUESTIONS

Advanced A-level chemistry - practise exam questions on the 1H NMR spectrum of phenol

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Jot down your responses and check out the answers:  ANSWERS

If you think there are any errors, please email me asap at chem55555@hotmail.com

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Q1. How many ΉH NMR signals does phenol normally show?

A. 2     B. 3     C. 4     D. 5


Q2. Where do the aromatic protons of phenol typically appear?

A. 0.5–1.5 ppm      B. 2–3 ppm      C. 6–8 ppm      D. 10–12 ppm


Q3. Where does the O–H proton of phenol typically appear?

A. 0.5–1.0 ppm     B. 1–5 ppm      C. 6–8 ppm      D. 9–12 ppm


Q4. What splitting pattern is normally observed for the O–H proton in phenol?

A. Doublet    B. Triplet    C. Broad singlet    D. Quartet


Q5. What splitting pattern is normally observed for phenol's aromatic protons?


 

Q6. What happens to phenol's O–H signal when D2O is added?

A. It becomes sharper    B. It shifts upfield    C. It disappears    D. It splits into a doublet


Q7. After adding D2O, how many ΉH NMR signals remain?

A. 1      B. 2      C. 3      D. 4


Q8. Which chemical shift region confirms the presence of an aromatic ring in phenol?

A. 0–2 ppm    B. 2–4 ppm     C. 6–8 ppm      D. 10–12 ppm


Q9. Which combination of features confirms phenol rather than benzene?

A. Aromatic multiplets + O–H peak at 9–12 ppm

B. Aromatic multiplets only

C. Singlet at 1 ppm + multiplet at 7 ppm

D. Broad peak at 3 ppm + aromatic multiplets


If you think there are any errors, please email me asap at chem55555@hotmail.com

I don't mind if students/teachers do a selected printout of these questions and answers.

Jot down your responses and check out the answers:  ANSWERS


The splitting pattern from proton spin-spin coupling effects is analysed using the n+1 rule for adjacent non-equivalent proton fields (n is the number of neighbouring protons in a non-equivalent different chemical environment) and applied to the 1H NMR spectrum of phenol.

Number of directly adjacent protons 1H causing splitting Splitting pattern produced from the n+1 rule on spin-spin coupling and the theoretical ratio of line intensities
0 means no splitting             1            
1 creates a doublet           1   1          
2 creates a triplet         1   2   1        
3 creates a quartet       1   3   3   1      
4 creates a quintet     1   4   6   4   1    
5 creates a sextet   1   5   10   10   5   1  
6 creates a septet 1   6   15   20   15   6   1

Key words & phrases: C6H6O C6H5OH Interpreting the proton H-1 NMR spectra of phenol, low resolution & high resolution proton nmr spectra of phenol, H-1 nmr spectrum of phenol, understanding the hydrogen-1 nmr spectrum of phenol, explaining the line splitting patterns from spin-spin coupling  in the high resolution H-1 nmr spectra of phenol, revising the H-1 nmr spectrum of phenol, proton nmr of phenol, ppm chemical shifts of the H-1 nmr spectrum of phenol, explaining and analyzing spin spin line splitting in the H-1 nmr spectrum, how to construct the diagram of the H-1 nmr spectrum of phenol, how to work out the number of chemically different protons in the structure of the phenol organic molecule, how to analyse the chemical shifts in the hydrogen-1 H-1 proton NMR spectrum of phenol using the n+1 rule to explain the spin - spin coupling ine splitting in the proton nmr spectrum of phenol deducing the nature of the protons from the chemical shifts ppm in the H-1 nmr spectrum of phenol examining the 1H nmr spectrum of  phenol analysing the 1-H nmr spectrum of phenol how do you sketch and interpret the H-1 NMR spectrum of phenol interpreting interpretation of the 1H proton spin-spin coupling causing line splitting in the NMR spectrum of phenol  assignment of chemical shifts in the proton 1H NMR spectrum of phenol formula explaining spin-spin coupling for line splitting for phenol aromatic hydroxyl functional group Explanatory diagram of the 1H H-1 proton NMR spectrum of the phenol molecule in terms of its molecular structure. Listing data of all the chemical shift peaks in ppm in the proton NMR spectrum of phenol. How to explain the H-1 NMR spectrum of phenol. The values of the integrated proton ratios in the 1-H NMR spectrum of the phenol molecule. How to work out the molecular structure of the phenol molecule from its proton NMR spectrum. The uses and distinctive features of the proton NMR spectrum of the phenol molecule explained. What does the H-1 proton NMR spectrum tell us about the structure and properties of the phenol molecule? How do you interpret the H-1 NMR spectrum of phenol How to interpret the H-1 NMR spectrum of phenol Explanatory diagram of the chemical shifts of the 1H H-1 proton NMR spectrum of the phenol molecule in terms of its molecular structure. Listing data of all the chemical shift peaks in ppm in the proton NMR spectrum of phenol. How to explain the H-1 NMR spectrum of phenol. The chemical shifts and  integrated values of the proton ratios in the 1-H NMR spectrum of the phenol molecule. How to work out the molecular structure of the phenol molecule from its proton NMR spectrum. The uses and distinctive features of the proton NMR spectrum of the phenol molecule explained. What does the H-1 proton NMR spectrum chemical shifts tell us about the structure and properties of the phenol molecule? explaining the spin-spin proton coupling effects in the 1H NMR spectrum of phenol. interpretation diagram explaining the proton splitting pattern produced from the n+1 rule and the theoretical ratio of chemical shift δ and values of intensities for the proton NMR spectrum lines of phenol


Links associated with phenol

The mass spectrum of phenol

The C-13 NMR spectrum of phenol

The infrared spectrum of phenol

Physical & chemical properties of phenol and some of its derivatives & uses

The chemistry of AROMATIC COMPOUNDS revision notes INDEX

H-1 proton NMR spectroscopy index

(Please read 8 points at the top of the 1H NMR index page)

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Website content © Dr Phil Brown 2000+. All copyrights reserved on revision notes, images, quizzes, worksheets etc. Copying of Doc Brown's pre-university advanced level chemistry website material is NOT permitted. Exam revision summaries & references to science course specifications are unofficial. These organic chemistry revision notes on spectroscopy (1H NMR spectrum of phenol, explanations of the detailed analysis and how to interpret the spectra notes) are suitable for use of pre-university students studying AQA advanced level chemistry, Edexcel advanced level chemistry, OCR advanced level chemistry, IB advanced level chemistry, WJEC (Eduqas) advanced level chemistry, CIE advanced level chemistry, CCEA advanced level chemistry, US grade 11-12 AP honors chemistry courses and they will also prove useful to 1st year undergraduate students of chemistry.
ANSWERS

Advanced A-level chemistry - practise exam questions on the 1H NMR spectrum of phenol

(c) doc b

If you think there are any errors, please email me asap at chem55555@hotmail.com

I don't mind if students/teachers do a selected printout of these questions and answers.


Q1. How many ΉH NMR signals does phenol normally show?

A. 2     B. 3     C. 4     D. 5

Correct answer: C

Explanation: Phenol shows four distinct proton environments:

  • Aromatic protons (four chemically distinct signals, often overlapping)
  • The O–H proton

At A‑level, these are treated as four signals: three aromatic regions + one OH.

Common misconception: Students often think “all aromatic protons give one signal,” but they are not equivalent.


Q2. Where do the aromatic protons of phenol typically appear?

A. 0.5–1.5 ppm      B. 2–3 ppm      C. 6–8 ppm      D. 10–12 ppm

Correct answer: C

Explanation: Aromatic protons appear in the 6–8 ppm region due to strong deshielding from the benzene ring.

Common misconception: Students sometimes place aromatic protons at ~4 ppm, confusing them with protons near electronegative atoms.


Q3. Where does the O–H proton of phenol typically appear?

A. 0.5–1.0 ppm     B. 1–5 ppm      C. 6–8 ppm      D. 9–12 ppm

Correct answer: D

Explanation: Phenol's O–H proton is highly deshielded by the aromatic ring and often appears around 9–12 ppm.

Common misconception: Students assume all O–H protons appear at 1–5 ppm (like alcohols), but phenols are much more downfield.


Q4. What splitting pattern is normally observed for the O–H proton in phenol?

A. Doublet    B. Triplet    C. Broad singlet    D. Quartet

Correct answer: C

Explanation: The O–H proton exchanges rapidly and appears as a broad singlet.

Common misconception: Students expect O–H to split adjacent aromatic protons — but exchange prevents coupling.


Q5. What splitting pattern is normally observed for phenol's aromatic protons?

A. Singlets only    B. Complex multiplets    C. Doublets only     D. Triplets only

Correct answer: B

Explanation: Aromatic protons couple with multiple neighbours, producing complex multiplets.

Common misconception: Students often expect simple n+1 patterns, but aromatic coupling is more complex.


 

Q6. What happens to phenol's O–H signal when D2O is added?

A. It becomes sharper    B. It shifts upfield    C. It disappears    D. It splits into a doublet

Correct answer: C

Explanation: The O–H proton exchanges with deuterium: C₆H₅OH + D₂O → C₆H₅OD + HOD Deuterium does not appear in ΉH NMR, so the O–H signal vanishes.

Common misconception: Students think the O–H peak “moves” — it actually disappears entirely.


Q7. After adding D2O, how many ΉH NMR signals remain?

A. 1      B. 2      C. 3      D. 4

Correct answer: C

Explanation: Only the aromatic protons remain, giving four distinct aromatic signals (often overlapping).

Common misconception: Students sometimes think aromatic protons collapse into one signal — they do not.


Q8. Which chemical shift region confirms the presence of an aromatic ring in phenol?

A. 0–2 ppm    B. 2–4 ppm     C. 6–8 ppm      D. 10–12 ppm

Correct answer: C

Explanation: Aromatic protons appear at 6–8 ppm, a key diagnostic region.

Common misconception: Students confuse aromatic protons with aldehyde protons (9–10 ppm).


Q9. Which combination of features confirms phenol rather than benzene?

A. Aromatic multiplets + O–H peak at 9–12 ppm

B. Aromatic multiplets only

C. Singlet at 1 ppm + multiplet at 7 ppm

D. Broad peak at 3 ppm + aromatic multiplets

Correct answer: A

Explanation: Phenol has aromatic multiplets and a highly deshielded O–H peak around 9–12 ppm. Benzene lacks the O–H proton.

Common misconception: Students think benzene and phenol have identical spectra — but phenol has an O–H signal.


If you think there are any errors, please email me asap at chem55555@hotmail.com

I don't mind if students/teachers do a selected printout of these questions and answers.

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